The figure shows a liquid of given density flowing steadily in horizontal tube of varying cross-section. Cross-sectional areas at A is 1.5 cm 2 , and B is 25 mm 2 , if the speed of liquid at B is 60 cm s -1 then (P A -P B ) is (Given P A and P B are liquid pressures at A and B points. Density 
= 1000 kg m -3 A and B are on the axis of tube)
Text Solution
Verified by ExpertsThe correct answer is:
C
Using Bernoulli's theorem,
…(i)
Using equation of continuity,
A A V A = A B V B
So,1.5x10 -4 xVA = 25x10 -6 xV B
Substituting in equation (i)
= 175 Pa
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